Respuesta :

[tex]\begin{gathered} 4x-2y=8 \\ 3x+4y=17 \\ \\ if\text{ we find y in the first equation} \\ \\ \\ 4x-8=2y \\ \frac{4x-8}{2}=y \\ y=2x-4 \\ \\ \text{then } \\ 3x+4y=17 \\ 3x+4(2x-4)=17 \\ 3x+8x-16=17 \\ 11x-16=17 \\ 11x=33 \\ x=\frac{33}{11} \\ x=3 \\ \\ \text{ and x=3, replacing x in y=2x-4} \\ y=2\cdot3-4 \\ y=6-4 \\ y=2 \\ \\ \text{the solution is (3,2)} \end{gathered}[/tex]

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