22
Explanation
[tex]-2+\sqrt[]{3x-2}=6[/tex]Step 1
a)add 2 in both sides
[tex]\begin{gathered} -2+\sqrt[]{3x-2}=6 \\ -2+\sqrt[]{3x-2}+2=6+2 \\ \sqrt[]{3x-2}=8 \end{gathered}[/tex]b) both sides to the 2 power
[tex]\begin{gathered} \sqrt[]{3x-2}=8 \\ (\sqrt[]{3x-2}^2=8^2 \\ 3x-2=64 \end{gathered}[/tex]c) again, add 2 in both sides.
[tex]\begin{gathered} 3x-2=64 \\ 3x-2+2=64+2 \\ 3x=66 \end{gathered}[/tex]d) finally, divide both sides by 3
[tex]\begin{gathered} 3x=66 \\ \frac{3x}{3}=\frac{66}{3} \\ x=22 \end{gathered}[/tex]I hope this helps you
