Given,
The diagram of the triangle is shown in the question.
For first diagram,
[tex]\begin{gathered} AC=DE \\ \angle A=\angle E \\ \angle B=\angle F \\ \therefore\Delta ABC\cong\Delta\text{DEF} \end{gathered}[/tex]
The triangles are congruent by Angle-angle-side (AAS) property.
For second diagram,
[tex]\begin{gathered} UW=XY \\ \angle U=\angle X \\ \angle W=\angle Y \\ \therefore\Delta UVW\cong\Delta\text{XYZ} \end{gathered}[/tex]
The triangles are congruent by Angle-side-angle (ASA) property.
For third diagram,
[tex]\begin{gathered} GI=JK \\ GH=KL \\ IH=JL \\ \therefore\Delta GHI\cong\Delta\text{JKL} \end{gathered}[/tex]
The triangles are congruent by Side-side-Side (SSS) property.
