The inequality function is given .
[tex]y\leq\frac{2}{3}x+1[/tex]
To draw the graph of the inequality function , first determine the coordinates of the function.
At x equal to 0.
[tex]y=\frac{2}{3}(0)+1[/tex][tex]y=1[/tex]
At y equal to 0.
[tex]0=\frac{2}{3}x+1[/tex][tex]-\frac{2}{3}x=1[/tex][tex]x=\frac{-3}{2}[/tex][tex]x=-1.5[/tex]
The coordinates at which the function satisfy are obtained as,
[tex](0,1),(-1.5,0)[/tex]
For the inequality of the function given is less than equal to that means the shaded region of the graph lies below the origin .
Therefore the garph of the inequality of the function is,
According to the options given A,B,C and D.
The correct option is A.
Reason : The ineqaulity graph is always represented by dashed line.
