To solve this problem we can use the Ideal gas law:
[tex]\frac{P_1\cdot V_1}{T_1}=\frac{P_2\cdot V_2}{T_2}[/tex]We deduce from the text:
V1=478mL
T1=29°C=302.15K
V2=1132mL
T2=62°C=335.15K
P2=1.7atm
Then we just have to solve for P1 and use the provided data:
[tex]P_1=\frac{P_2\cdot V_2}{T_2\cdot V_1}\cdot T_1=\frac{1.7atm\cdot1132mL}{335.15K\cdot478mL}\cdot302.15k=3.63atm[/tex]The initial pressure was P1= 3.63atm
