We have the next informations
1990 ------ 2400
2000-------- 4000
the year 1990 represents x=0
for 2000 passed 10 years son x=10
we have then the next points
(0,2400) =(x1,y1)
(10,4000) =(x2,y2)
First we need to calculate the slope
[tex]m=\frac{y2-y1}{x2-x1}[/tex][tex]m=\frac{4000-2400}{10-0}=\frac{1600}{10}=160[/tex]then we can calculate the linear equation
[tex]y-y1=m(x-x1)[/tex][tex]y-2400=160(x-0)[/tex]the linear equation is
[tex]y=160x+2400[/tex]the correct answer is B