x² +y² = 9, (x+2)² +(y +5)² = 16
1.) Let's find the equation of the circle given C(0,0), r=3 and b) C(-2,-5) and r =4
The equation of a circle is given by
(x-h)²+(y-k)²= r² C(h, k)
2) Since the Center of the Circle has been given, then let's plug it in, and the radius as well
a) C(0,0) and r=3
(x-h)²+(y-k)²= r²
(x-0)²+(y-0)²= 3²
x² +y² = 9 Circle centered at the origin of the Cartesian Plane
b) C(-2,-5) and r =4
(x-h)²+(y-k)²= r²
(x+2)² +(y +5)² = 16 Since the coordinate of the center are negative
