[tex]\begin{gathered} 2^2=(\sqrt[]{2})^2+opposite^2 \\ 4=2+O^2 \\ 4-2=O^2 \\ O^2=2 \\ O=\sqrt[]{2} \end{gathered}[/tex][tex]\begin{gathered} \text{Sine }\theta=\frac{opposite}{\text{hypotenuse}} \\ \text{Sine }\theta=\frac{\sqrt[]{2}}{2} \end{gathered}[/tex]
