RurikA456945
RurikA456945
30-10-2022
Mathematics
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please help me ASAP!!!
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FischerS673693
FischerS673693
30-10-2022
[tex]\begin{gathered} f(x)=2x^3+6 \\ y=2x^3+6 \\ y-6=2x^3 \\ \frac{y-6}{2}=x^3 \\ x=\sqrt[3]{\frac{y-6}{2}} \\ f^{-1}(x)\text{ =}\sqrt[3]{\frac{x-6}{2}} \end{gathered}[/tex]
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