We have a direct variation between x and y.
We can write this as:
[tex]y=k\cdot x[/tex]
where k is a constant.
Knowing one point of the relation, like (-2,-8) we can calculate k as:
[tex]k=\frac{y}{x}=\frac{-8}{-2}=4[/tex]
Then, if we have the point (x,36), we have to calculate the value of x.
As we know that y = 36 and k = 4, we can find x as:
[tex]\begin{gathered} y=k\cdot x \\ x=\frac{y}{k}=\frac{36}{4}=9 \end{gathered}[/tex]
Answer: the missing value is x = 9
