Answer:
Explanation:
Given f(x) defined below:
[tex]f\mleft(x\mright)=x^4-11x^3+40x^2-48x[/tex]
To find the zeros, set f(x) equal to 0.
[tex]x^4-11x^3+40x^2-48x=0[/tex]
First, observe that we can factor out x.
[tex]\begin{gathered} x(x^3-11x^2+40x-48)=0 \\ \implies x=0\text{ or }x^3-11x^2+40x-48=0 \end{gathered}[/tex]
Given that x=3 is a zero of the function, we divide using synthetic division to find the other factors.
