Given the table;
Since the function is linear. The general equation is given as;
[tex]\begin{gathered} y=mx+c \\ \text{Where;} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ (-8,-2),(-4,0) \\ x_1=-8,y_1=-2,x_2=-4,y_2=0 \end{gathered}[/tex][tex]\begin{gathered} m=\frac{0-(-2)}{-4-(-8)} \\ m=\frac{2}{4} \\ m=\frac{1}{2} \end{gathered}[/tex]
Now, let's use the third point to get the intercept c of the line. We have;
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