POSSIBLE POINTS 7.69 An architect's blueprint for a new house shows the pool being 2 inches wide. If the scale used to create the blueprint is 0.25 in. = 3 ft., what is the actual width of the pool?

Respuesta :

[tex]\begin{gathered} \text{Let w represents the actual width} \\ \text{ scale is 0.25in = 3 ft} \\ \text{ }\frac{0.25in}{3\text{ ft}}\text{ = }\frac{2}{w} \\ \\ 0.25w=\text{ 2 x 3} \\ 0.25w=6 \\ w=\frac{6}{0.25} \\ w=24 \end{gathered}[/tex]

The actual width of the pool is 24 ft