The given inequality is
[tex]\frac{1}{3}(9x+27)>x+33[/tex]Simplify the left side
[tex]3x+9>x+33[/tex]Subtract x and 9 from each side
[tex]\begin{gathered} 3x-x+9-9>x-x+33-9 \\ 2x>24 \end{gathered}[/tex]Divide each side by 2
[tex]\begin{gathered} \frac{2x}{2}>\frac{24}{2} \\ x>12 \end{gathered}[/tex]The answer should be D
