Given the following expression:
[tex]\frac{63v^{10}}{9v^2}[/tex]We will use the following rule of the exponents:
[tex]\frac{a^m}{a^n}=a^{m-n}[/tex]So, the given expression will be as follows:
[tex]\frac{63v^{10}}{9v^2}=\frac{63}{9}v^{10-2}=7v^8[/tex]So, the answer will be:
[tex]7v^8[/tex]