The nth term of a sequence is given by the formula:
[tex]T_n_{}=a+(n-1)d[/tex]
Where
[tex]\begin{gathered} T_n=\text{nth term} \\ a=\text{ first term} \\ n=\text{ number of terms} \\ d=\text{ common difference} \end{gathered}[/tex]
From the question given
We are told that the first term is -17
the common difference is 5
We will simply substitute these values into the formula
[tex]T_n=-17+(n-1)\times5[/tex]
Simplifying
we will have
[tex]\begin{gathered} T_n=-17+5n-5 \\ T_n=5n-17-5 \end{gathered}[/tex]
Simplifying further, we will have
[tex]T_n=5n-22[/tex]
So If we compare the answer above with what is required in the question, we will have
[tex]a_n=5n-22[/tex]
Therefore we will have
