First, we find the area of the base,
The base is a rectangle
[tex]\text{Area of base = length }\times\text{ width}[/tex]
Length = 24m, Width = 4m
Therefore,
[tex]\begin{gathered} \text{Area of base = 24m }\times\text{ 4m} \\ \text{Area of base = 96m}^2 \end{gathered}[/tex]
Finding, Lateral area
[tex]\begin{gathered} \text{Lateral Area = sum of area of sides} \\ \text{Lateral Area = 2(lw) + 2(wh)} \end{gathered}[/tex]
Length = 24m, width = 4m, height = 2m
Therefore,
[tex]\begin{gathered} \text{Lateral Area = 2(24m }\times\text{ 4m) + 2(4m }\times\text{ 2m)} \\ LateralArea=2(96m^2)+2(8m^2\text{)} \\ \text{Lateral Area = 192m}^2+16m^2 \\ \text{Lateral Area = 208m}^2 \end{gathered}[/tex]
Finding the total surface area,
The total surface area is given as
[tex]\text{Total Surface Area =2lh + 2lw + 2wh}[/tex]
Therefore,
[tex]\begin{gathered} \text{Total Surface area = 2(24m }\times\text{ 2m) + 2(24m }\times4m)\text{ + 2(4m }\times2m) \\ \text{Total Surface Area = 2(48m}^2)\text{ + 2}(96m^2)+2(8m^2) \\ \text{Total Surface Area =96m}^2+192m^2+16m^2 \\ \text{Total Surface Area = 304m}^2 \end{gathered}[/tex]
