Respuesta :
Since the only force acting on the stone is its weight the stone only accelerates in the y-direction; this means the following:
• Horizontally we have a uniform rectilinear motion in this direction.
,• Vertically we have a uniform acceleration motion.
From the previous discussion we readily conclude that after 1 second the horizontal component of the velocity will be 8 m/s.
Now, to determine the y component of the velocity we can use the equation:
[tex]a=\frac{v_f-v_0}{t}[/tex]in the vertical direction we know that:
The acceleration is -10 m/s^2
The initial velocity is zero.
The time is 1 s.
Plugging these on the equation above and solving for the velocity we have:
[tex]\begin{gathered} \frac{v_f-0}{1}=-10 \\ v_f=-10 \end{gathered}[/tex]Therefore, after one second we have:
[tex]\begin{gathered} v_x=8\text{ m/s} \\ v_y=-10\text{ m/s} \end{gathered}[/tex]