EXPLANATION:
Given;
We are given a square with two unshaded portions labelled A and B.
Required;
We are required to find the area of the sections A and B.
Step-by-step solution;
To do this, first of all take note that the section labelled A has a side with length 4ft. The other side is also 4 ft. We know this because the corresponding side shows 4ft + 4ft.
This means what we have is a sector of a circle with radius 4ft.
To calculate the area of sector A (and B), we shall apply the formula;
Formula;
[tex]\begin{gathered} Area\text{ }of\text{ }a\text{ }sector: \\ Area=\frac{\theta}{360}\times\pi r^2 \end{gathered}[/tex]
Note that the variables are;
[tex]\theta=90\degree,r=4,\pi=3.14[/tex]
We can now substitute these values and solve;
[tex]Area=\frac{90}{360}\times3.14\times4^2[/tex][tex]Area=\frac{1}{4}\times3.14\times16[/tex][tex]Area=12.56ft^2[/tex]
Therefore, the area of the sector A and B are;
ANSWER:
[tex]\begin{gathered} A=12.56ft^2 \\ B=12.56ft^2 \end{gathered}[/tex]
Note that the dimensions are the same for sectors A and B. Hence, the areas are the same for both.
