a. if a circle has a circumference of 8π cm, what is it's area? b. If a circle of radius r, and a square with a side length b have equal areas, express r in terms of b.

Respuesta :

Given:

(a) Circumference of a circle is

[tex]8\pi[/tex]

To find: Area of circle

Circumference of circle is given as:

[tex]\text{circumference}=2\pi r=8\pi[/tex]

where, r is radius of circle

On solving,

[tex]\begin{gathered} 2\pi r=8\pi \\ r=4 \end{gathered}[/tex]

Area of circle is given by formula:

[tex]\begin{gathered} \text{area=}\pi\times r^2^{} \\ =\pi\times4^2 \\ =16\pi \end{gathered}[/tex]

Hence, area of circle is :

[tex]=16\pi\text{ squares cm}[/tex]

(b) Radius of circle is given 'r' and square of length is given 'b'

and they have equal areas.

To find: r in terms of b.

According to the question,

Area of circle= Area of square

[tex]\begin{gathered} \pi\times r^2=b^2 \\ r^2=\frac{b^2}{\pi} \\ r=\sqrt[]{\frac{b^2}{\pi}} \\ =\frac{b}{\sqrt[]{\pi}} \end{gathered}[/tex]

Hence,

[tex]r=\frac{b}{\sqrt[]{\pi}}[/tex]