We have the point
A(-6,2)
a) In order to find the coordinates of the A' when A is reflected across y=x we have the next rule
[tex](x,y)\rightarrow(y,x)[/tex]
therefore
A'(2,-6)
b) In order to find the coordinates of A' when A is reflected across y=-x we have the next rule
[tex](x,y)\rightarrow(-y,-x)[/tex]
therefore
A'(-2,6)
As we can see in the next image
where y=x is the line in green and the line in blue is y=-x
