Solution
For this case we can set up equal the two equations and we got:
[tex]\frac{1}{3}x+2=-3x^2-5x-4[/tex]
And solving for x w ehave:
[tex]3x^2+\frac{16}{3}x+6=0[/tex]
We can multiply both sides of the equation by 3 and we got:
[tex]9x^2+16x+18=0[/tex]
And we can solve this using the quadratic formula and we got:
[tex]x=\frac{-16\pm\sqrt[]{16^2-4(9)(18)}}{2\cdot9}[/tex]
Since the discriminant is lower than 0 we can conclude that this system has 0 solutions and we can verify with the graph given by:
