If AE = x + 2 and BD = 4x – 16, then the length of ACI is A6 B. 10 C. 12 D. 24

Remember that
the diagonals in a rectangle are congruent and bisect each other
that means
AE=BD/2
substitute the given values
x+2=(4x-16)/2
solve for x
2x+4=4x-16
4x-2x=4+16
2x=20
x=10
AC=BD=4(10)-16=24