Respuesta :

[tex]\frac{64a^3b^5}{16ab^8}[/tex]

Using the following properties:

[tex]\begin{gathered} x^y\cdot x^z=x^{y+z} \\ a^{-n}=\frac{1}{a^n},n\ne0 \end{gathered}[/tex][tex]\frac{64a^3b^5}{16ab^8}=\frac{64}{16}\cdot a^3\cdot a^{-1}\cdot b^5\cdot b^{-8}=4a^2b^{-3}=\frac{4a^2}{b^3}[/tex]

Otras preguntas