Let's find the vertical assymptotes. Therefore, the vertical assymptotes is found when we equates the denominator to zero.
[tex]\begin{gathered} (x+5)^2=(x+5)(x+5) \\ (x+5)(x+5)=0 \\ x=-5\text{ } \\ 0r\text{ } \\ x=-5 \end{gathered}[/tex]
The graph of the function is therefore,
[tex]f(x)=\frac{1}{(x+5)^2}[/tex]
