Given,
The mass of the planet, M=6.5×10²⁴ kg
The radius of the planet, r=70.0×10⁵ m
The gravitational constant, G=6.67×10⁻¹¹ m³kg⁻¹s⁻²
The escape velocity is the minimum initial velocity that an object needs to have in order to escape the gravitational pull of a planet.
The escape velocity is given by,
[tex]v=\sqrt[]{\frac{2GM}{r}}[/tex]On substituting the known values,
[tex]\begin{gathered} v=\sqrt[]{\frac{2\times6.67\times10^{-11}\times6.5\times10^{24}}{70.0\times10^5}} \\ =11129.75\text{ m/s} \\ =11.13\text{ km/s} \end{gathered}[/tex]Thus the escape velocity of the planet is 11129.75 m/s or 11.13 km/s
