System
[tex]\begin{gathered} -6x-3y=-6\text{ (1)} \\ 2x+3y=-6\text{ (2)} \end{gathered}[/tex]Let's sum equations 1 and 2
[tex]\begin{gathered} (1)+(2) \\ -6x-3y+2x+3y=-6-6 \\ -6x+2x-3y+3y=-12 \\ -4x=-12 \\ x=\frac{-12}{-4} \\ x=3 \end{gathered}[/tex]Now let's determine the value for y using (2)
[tex]\begin{gathered} 2x+3y=-6 \\ 3y=-6-2x \\ y=\frac{-6-2x}{3} \\ y=\frac{-6-2\cdot(3)}{3} \\ y=\frac{-6-6}{3} \\ y=-\frac{12}{3} \\ y=-4 \end{gathered}[/tex]The answer would be x = 3, y = -4
