Solution
Part c
AB= AC
3x+40 = 5x+10
Solving for x we got:
40-10 = 5x-3x
30= 2x
x= 15
then we can find:
BC= 15+30=45
Part d
For this case the congurent angles are:
< ABC= < ACB
Part e
4x +10 +4x +10+ 6x +48= 180
14x +68 = 180
14x = 180-68
14x = 112
x = 112/14 =8
m< ABC= 4*8 +10 = 32+10 = 42
