The annual depreciation can be found:
[tex]3.5years\to\frac{29000}{2}=14500^{}[/tex][tex]\begin{gathered} 7years\to\frac{14500}{2}=7250 \\ \end{gathered}[/tex][tex]10.5years\to\frac{7250}{2}=3625[/tex][tex]14years\to\frac{3625}{2}=1812.5[/tex][tex]17.5years\to\frac{1812.5}{2}=906.25[/tex][tex]21years\to\frac{906.25}{2}=453.125[/tex]Now, using cross multiplication:
21---------------------->453.125
20------------------------>?
[tex]\begin{gathered} \frac{21}{20}=\frac{453.125}{?} \\ \text{?}=863.095 \end{gathered}[/tex]The value of the car will be $863
