Given:
y = 3x - 2
The point C(2, 3) is translated along a vector that is parallel to the line above.
Using the slope intercept form:
y = mx + b
where m is the slope
Since they are parallel lines, they have equal slope.
Thus, m = 3
Given the points: (x, y) ==> (2, 3)
We have:
y = mx + b
3 = 3(2) + b
Solve for b:
3 = 6 + b
b = 3 - 6
b = -3
We now have the equation:
y = 3x - 3
Given that the vector has a magnitude of √10, the possible images of point C is:
