Given:
In the first option, Charlie can pay $39 for unlimited rides,
In the second option, Charlie can pay $15 for admission plus $1 per ride.
Required:
We need to find the number of rides that the two options wind up costing him the same amount.
Explanation:
Let C be the cost of the ride.
Let r be the number of the ride.
Consider the first option.
[tex]C=39[/tex]Consider the second option.
[tex]C=15+r(1)[/tex]Substitute C=39 in this equaiton.
[tex]39=15+r(1)[/tex]Substract 15 from both sides of the equation.
[tex]39-15=15+r(1)-15[/tex][tex]24=r[/tex][tex]r=24\text{ rides.}[/tex]The number of rides that the two options wind up costing him the same amount is 24 rides.
The cost of the ride is C =39.
Final answer:
The number of rides =24.
The cost of the rides =39.