There are a number of fruits in a bag. 2/5 of it is mango and the rest is banana. If 1/3 of the bananas or 12 banana are removed, how many mangoes are in the bag?

Respuesta :

Let the number of fruits in the bag be x.

Given:

[tex]\begin{gathered} \text{Mango = }\frac{2}{5}x \\ \text{Banana = }\frac{3}{5}x \end{gathered}[/tex]

From the statement: 1/3 of the bananas or 12 bananas are removed. We can represent this mathematically as:

[tex]\frac{1}{3}\text{ }\times\text{ }\frac{3}{5}x\text{ = 12}[/tex]

Solving for x:

[tex]\begin{gathered} \frac{1}{5}x\text{ = 12} \\ \text{Cross}-\text{Multiply} \\ x\text{ = 5 }\times\text{ 12} \\ =\text{ 60} \end{gathered}[/tex]

Recall that the number of mangoes in the bag is:

[tex]=\text{ }\frac{2}{5}x[/tex]

Substituting:

[tex]\begin{gathered} \text{Number of mangoes = }\frac{2}{5}\text{ }\times\text{ 60} \\ =\text{ 24} \end{gathered}[/tex]

Hence, there are 24 mangoes in the bag

Answer:

24 mangoes