We will have the following:
7x - 32 & 5x -27 & 180 -(9x -8)
The last onse since we are given the exterior angle that is supplementary from the angle we need, we then proceed as follows:
[tex](7x-32)+(5x-27)+(180-9x+8)=180[/tex]
That since the sum of all internal angles of a triangle equals 180°, we now solve for x:
[tex]\Rightarrow3x+129=180\Rightarrow3x=51\Rightarrow x=17[/tex]
Now that we have x, we then replace in the functions, and we will get:
[tex]x=17[/tex][tex]\text{JKL}=7(17)-32\Rightarrow JKL=87[/tex][tex]\text{KJL}=5(17)-27\Rightarrow KJL=58[/tex][tex]\text{KLJ}=180-9(17)+8\Rightarrow KLJ=35[/tex][tex]\text{KLM}=9(17)-8\Rightarrow KLM=145[/tex]
