Given:
The total number of students is,
2+4+9+3=18.
The number of students who play both sports and instruments is 2.
To find the probability that a student who plays a sport also plays an instrument:
So, the probability that a student who plays a sport also plays an instrument is,
[tex]\begin{gathered} P(E)=\frac{\text{No. of students who play both}}{\text{Total number of students}} \\ =\frac{2}{18} \\ =\frac{1}{9} \end{gathered}[/tex]
Thus, the answer is,
[tex]\frac{1}{9}[/tex]
