From the graph, we see that the position of the center and the radius of the circle are:
From the general form of the equation of a circle:
[tex]r^2=(x-x_0)^2+(y-y_0)^2[/tex]
Where r is the radius of the circle and (x₀, y₀) is the position of the center. From the problem, we identify:
[tex]\begin{gathered} r=3 \\ (x_0,y_0)=(-3,7) \end{gathered}[/tex]
Finally, using the general form of the circle equation:
[tex]\begin{gathered} 3^2=(x-(-3))^2+(y-7)^2 \\ \\ \therefore(x+3)^2+(y-7)^2=9 \end{gathered}[/tex]
