Respuesta :
9.
[tex](\frac{2}{9})^3\times(\frac{2}{9})^{-6}=(\frac{2}{9})^{2x-1}[/tex]express the left hand side as:
[tex]\begin{gathered} (\frac{2}{9})^{3-6}=(\frac{2}{9})^{2x-1} \\ (\frac{2}{9})^{-3}=(\frac{2}{9})^{2x-1} \end{gathered}[/tex]The exponents must be equal, therefore:
[tex]\begin{gathered} -3=2x-1 \\ \end{gathered}[/tex]solve for x:
[tex]\begin{gathered} 2x=-2 \\ x=-\frac{2}{2} \\ x=-1 \end{gathered}[/tex]