Suppose that ABC is isosceles with base CB.Suppose also that m L C= (2x+24)° and m L B = (3x+ 13)°.Find the degree measure of each angle in the triangle.

Solution
Since it's an Isosceles triangle,
m∠C = m∠B
2x + 24 = 3x + 13
[tex]\begin{gathered} 24-13=3x-2x \\ \\ \Rightarrow x=11 \end{gathered}[/tex]when x = 11
m∠C = (2(11) + 24) = 46
=> m∠B = 46
Since m∠A + m∠B + m∠C = 180
=> m∠A = 180 - m∠B - m∠C = 180 - 46 - 46 = 88
=> m∠A = 88
=> m∠B = 46
=> m∠C = 46