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The diagram of an isosceles trapezoid is labeled below. If the area of the trapezoid is 168 square units, the what is the height, h, out of the trapezoid?

Respuesta :

[tex]\begin{gathered} \text{Area =}\frac{(B+b)\cdot h}{2} \\ 2\cdot\text{Area}=(B+b)\cdot h \\ h=\frac{2\cdot Area}{B+b} \\ h=\frac{2\cdot168}{19+9} \\ h=\frac{336}{28} \\ h=12 \\ \end{gathered}[/tex]

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