The mean of each player's batting averages can be calculated as follows;
[tex]\text{Mean}=\frac{\Sigma data}{observed\text{ data}}[/tex]
For the first player, the mean shall be;
[tex]\begin{gathered} \text{Mean}=\frac{0.318+0.369+0.322+0.365+0.317+0.274}{6} \\ \text{Mean}=\frac{1.965}{6} \\ \text{Mean}=0.3275 \\ \text{Mean}\approx0.328\text{ (rounded to the nearest thousandth)} \end{gathered}[/tex]
To determine the range (that is, the difference between the highest value and the least value), we begin by arranging the data in order from least to highest as follows;
[tex]\text{Values}=0.274,0.317,0.318,0.322,0.365,0.369[/tex]
The range therefore is;
[tex]\begin{gathered} \text{Range}=0.369-0.274 \\ \text{Range}=0.095 \end{gathered}[/tex]
For the second player, the mean shall be;
[tex]\begin{gathered} \text{Mean}=\frac{0.313+0.327+0.367+0.245+0.333+0.385}{6} \\ \text{Mean}=\frac{1.97}{6} \\ \text{Mean}=0.3283 \\ \text{Mean}\approx0.328\text{ (rounded to the nearest thousandth)} \end{gathered}[/tex]
The range for the second player is;
[tex]\text{Values}=0.245,0.313,0.327,0.333,0.367,0.385[/tex][tex]\begin{gathered} \text{Range}=0.385-0.245 \\ \text{Range}=0.14 \end{gathered}[/tex]
Therefore, our calculations have shown that both players recorde
