Answer:
The solution to the equation is;
[tex]u=-10[/tex]Explanation:
Given the equation;
[tex]4(u+3)-6u=32[/tex]let us expand and solve;
[tex]\begin{gathered} 4u+12-6u=32 \\ 4u-6u+12=32 \\ -2u+12=32 \\ -2u=32-12 \\ -2u=20\text{ ------divide both sides by -2} \\ u=\frac{20}{-2} \\ u=-10 \end{gathered}[/tex]Therefore, the solution to the equation is;
[tex]u=-10[/tex]