A carton of eggs contains 7 good eggs and 3 cracked eggs. If 4 eggs are selectedat random fromthe carton, what is the probability that 3 eggs are good and one egg is cracked?

Respuesta :

Answer:

[tex]P=\frac{1}{7}[/tex]

Step-by-step explanation:

The probability is represented by the following equation:

[tex]P(A)=\frac{Number\text{ of favorable outcomes}}{\text{ Total number of possible outcome}}[/tex]

If the total of eggs is 10. 7 are good eggs and 3 are cracked eggs. Then, the probability of selecting randomly 4 eggs and 3 of them are good and one egg is cracked:

Probability of Two Events Occurring Together: Independent

Just multiply the probability of the first event by the second.

[tex]\begin{gathered} P=\frac{3}{7}*\frac{1}{3} \\ P=\frac{1}{7} \end{gathered}[/tex]