Using the degree approach;
[tex]\pi=180^o[/tex]Then;
[tex]\begin{gathered} \sin 7(\frac{\pi}{6})=\sin 210^o \\ \sin 7(\frac{\pi}{6})=-\frac{1}{2} \end{gathered}[/tex]That is, the opposite is -1, and the hypotenuse is 2.
Also, following the image below;
Recall that;
[tex]\begin{gathered} \sin \theta=\frac{opposite}{hypotenuse} \\ \end{gathered}[/tex]The opposite side is the side facing the angle, and the side facing angle 30 is -1. Then the third side is the adjacent.
[tex]\sin 7(\frac{\pi}{6})=-\frac{1}{2}[/tex]
