The length of a rectangle is 5M less than twice the width, and the area of the rectangle is 52 m^2. Find the dimensions of the rectangle. Length:Width:

Respuesta :

Let l be the length of the rectangle, then we can set the following equation:

[tex]l=2w-5m\text{.}[/tex]

Where w is the width of the rectangle. Now, the formula for the area of a rectangle is:

[tex]A=lw\text{.}[/tex]

Solving the above equation for l, we get:

[tex]l=\frac{A}{w}\text{.}[/tex]

Substituting l=A/w in the first equation we get:

[tex]\frac{A}{w}=2w-5m\text{.}[/tex]

Solving for w, and considering that A=52 m²we get:

[tex]\begin{gathered} A=(2w-5m)w, \\ A=2w^2-(5m)w, \\ 52m^2=2w^2-(5m)w, \\ 2w^2-(5m)w-52m^2=0, \\ (2w-13m)(w+4m)=0, \\ w=\frac{13}{2}m\text{.} \end{gathered}[/tex]

Substituting w=4m in the first equation we get:

[tex]l=13m-5m=8m\text{.}[/tex]

Answer:

Length: 8 m,

Width: 6.5 m.