Respuesta :
We will start by determining the new concentration of the HCl solution. To do this we will calculate the dilution factor then use this dilution factor to calculate the new concentration:
[tex]\begin{gathered} Dilutionfactor(D.F)=\frac{total\text{ }volume}{aliquot\text{ }volume}=\frac{stock}{working} \\ D.F=\frac{900mL}{2.00mL} \\ D.F=450 \\ \\ D.F=\frac{0.15M}{x} \\ 450=\frac{0.15M}{x} \\ x\times450=0.15M \\ x=\frac{0.15M}{450} \\ x=3.33\times10^{-4}M \end{gathered}[/tex]Now we will calculate the pH,
[tex]\begin{gathered} pH=-log[H^+] \\ pH=-log[3.33\times10^{-4}] \\ pH=3.48 \end{gathered}[/tex]Answer: The pH of the diluted solution 3.48,
