To solve this problem, we're going to use the formula of molarity:
[tex]\text{Molarity (M)=}\frac{mole\text{s of solute}}{liter\text{s of solution}}\text{.}[/tex]We have to find the number of moles in 106 g of Na. The molar mass of Na can be found in the periodic table, which is 23 g/mol. The conversion would be:
[tex]106\text{ g Na}\cdot\frac{1\text{ mol Na}}{2\text{3 g Na}}=4.61\text{ moles Na.}[/tex]Finally, we replace the moles (4.61 moles) and the liters of solution (6.00 L) in the formula:
[tex]\text{Molarity = }\frac{4.61\text{ moles}}{6.00\text{ L}}=0.768\text{ M.}[/tex]The molarity of the solution would be 0.768 M.
