SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Draw the given figure
STEP 2: Write the formula for the area of the figure
[tex]Area_{figure}=Area\text{ of A + Area of B}[/tex]
STEP 3: Find the area of A
[tex]\begin{gathered} length\text{ of Reactangle A}=2in \\ width\text{ of Rectangle B}=6in \\ Area\text{ of A}=length\times width \\ Area\text{ of A}=2in\times6in=12in^2 \end{gathered}[/tex]
STEP 4: Find the Area of B
[tex]\begin{gathered} length\text{ of Rectangle B}=(6-2)in=4in \\ width\text{ of Rectangle B}=2in \\ Area\text{ of Rectangle B}=4in\times2in=8in^2 \end{gathered}[/tex]
STEP 5: find the area of the figure
[tex]\begin{gathered} According\text{ to formula in step 2,} \\ Area_{figure}=12in^2+8in^2=20in^2 \end{gathered}[/tex]
Hence, the area of the given figure is 20in²
