Given a matrix,
a b
c d
the determinant would be ad - bc
Fof the first matrix, the determinant would be
[tex]\begin{gathered} \frac{3}{2}\times\frac{1}{4}-\frac{1}{2}\times-\frac{1}{4} \\ =\text{ }\frac{3}{8}+\frac{1}{8} \\ The\text{ denominator is the same. We just add the numerator. It becomes} \\ \frac{4}{8} \\ =\text{ }\frac{1}{2} \end{gathered}[/tex]
For the second matrix, the determinanat would be
[tex]\begin{gathered} -\text{ 3}\times-\text{ 6 - (- 1 }\times-\text{ 4)} \\ =\text{ 18 - 4} \\ =\text{ 14} \end{gathered}[/tex]
