For the arm shown in the picture below, calculate the torque, and the find the “torque load” assuming a current limit of 2 amps. Use the motor specification given in the table and the formulas to solve the problem. Video how your solved the problem (using a smart phone) and submit it to this assignment.

[tex]\begin{gathered} Torque\text{ load=}\frac{(\text{current limit-fre}e\text{current)}\cdot\text{stall torque}}{(\text{stall current-}fre\text{ current)}} \\ \end{gathered}[/tex]

hence

Step 1

Torque load

a)Let

[tex]\begin{gathered} free\text{ sp}eed=100\text{ RPM} \\ Stalltorque=1.67\text{ N}\cdot m \\ Stall\text{ current=}4.8\text{ Amps} \\ fre\text{ current=}0.37\text{ Amps} \\ \text{Current limit= 2 Amps} \end{gathered}[/tex]

b)now, replace in the formula

[tex]\begin{gathered} Torque\text{ load=}\frac{(\text{current limit-fre}e\text{ current)}\cdot\text{stall torque}}{(\text{stall current-}fre\text{ current)}} \\ Torque\text{ load=}\frac{(2\text{ Amps-}0.37\text{ amps)}\cdot1.67\text{ N}\cdot m}{(4.8\text{ Amps-}0.37\text{ Amps)}} \\ Torque\text{ load=}\frac{(1.63\text{amps)}\cdot1.67\text{ N}\cdot m}{(4.43\text{ Amps)}} \\ Torque\text{ load=0.61 N}\cdot m \end{gathered}[/tex]

therefore, the answer is

torque load: 0.61 N*m

Step 2

Torque:

the torque is given by the expression

[tex]\text{Torque}=\text{ force}\cdot\text{ distance}[/tex]

so , after checking the imagen

let

distance=0.5 m

force=30 N

now,replace and calculate

[tex]\begin{gathered} \text{Torque}=\text{ force}\cdot\text{ distance} \\ \text{Torque = 30 N}\cdot0.5\text{ m} \\ \text{Torque =}15\text{ N}\cdot m \end{gathered}[/tex]

so

torque: 15 N*m

I hope this helps you