Hi, can you help me to solve this exercise, please!!

So here we have the following right triangle:
To find the value of the measure of the segment DE, we could use the trigonometric functions as follows:
We know that the tangent function relations the opposite side of the angle of a right triangle and its adjacent side. So, we could write:
[tex]\begin{gathered} \tan (32)=\frac{DE}{8} \\ \\ DE=8\tan (32) \\ DE=4.99\approx5.0 \end{gathered}[/tex]Therefore, the measure of the segment DE is 5.