For a normal distribution with a mean of μ = 85 anda standard deviation of o= 20, find the proportion ofthe population corresponding to each of the following.a. Scores greater than 89b. Scores less than 72c. Scores between 70 and 100

Respuesta :

ANSWER:

a. 0.4207

b. 0.2578

c. 0.5468

STEP-BY-STEP EXPLANATION:

Given:

μ = 85

σ = 20

Now, the probabilities are obtained, after obtaining the z-score for the given corresponding sample data points. We calculate the value of z as follows:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

We calculate for each case:

a. P( x > 89)

[tex]\begin{gathered} P\left(x>89\right)=1-P\left(x<89\right) \\ \\ z=\frac{89-85}{20}=\frac{4}{20}=0.2 \end{gathered}[/tex]

We locate this value in the normal table:

Therefore:

[tex]\begin{gathered} P(x\gt89)=1-P(x\lt89)=1-0.5793 \\ \\ P(x\gt89)=0.4207 \end{gathered}[/tex]

b. P (x < 72)

[tex]\begin{gathered} P\left(x<72\right) \\ \\ z=\frac{72-85}{20}=\frac{-13}{20}=0.65 \end{gathered}[/tex]

We locate this value in the normal table:

Therefore:

[tex]P(x<72)=0.2578[/tex]

c. P (70 < x < 100)

[tex]\begin{gathered} P(70We locate this value in the normal table:

Therefore:

[tex]\begin{gathered} P(70\lt x\lt100)= P(x\lt100)- P(x\lt70) \\ \\ P(70\lt x\lt100)=0.7734-0.2266 \\ \\ P(70\lt x\lt100)=0.5468 \end{gathered}[/tex]

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